def iou(bb_test,bb_gt):
"""
Computes IUO between two bboxes in the form [x1,y1,x2,y2]
"""
xx1 = np.maximum(bb_test[0], bb_gt[0])
yy1 = np.maximum(bb_test[1], bb_gt[1])
xx2 = np.minimum(bb_test[2], bb_gt[2])
yy2 = np.minimum(bb_test[3], bb_gt[3])
w = np.maximum(0., xx2 - xx1)
h = np.maximum(0., yy2 - yy1)
wh = w * h
o = wh / ((bb_test[2]-bb_test[0])*(bb_test[3]-bb_test[1])
+ (bb_gt[2]-bb_gt[0])*(bb_gt[3]-bb_gt[1]) - wh)
print("IOU :{}".format(o))
return(o)
def convert_bbox_to_z(bbox):
"""
Takes a bounding box in the form [x1,y1,x2,y2] and returns z in the form
[x,y,s,r] where x,y is the centre of the box and s is the scale/area and r is
the aspect ratio
w = x2-x1
h = y2-y1
x = x1+(x2-x1)/2.
y = y1+(y2-y1)/2.
"""
w = bbox[2]-bbox[0]
h = bbox[3]-bbox[1]
x = bbox[0]+w/2.
y = bbox[1]+h/2.
s = w*h
r = w/float(h)
return np.array([x,y,s,r]).reshape((4,1))
"""
def convert_x_to_bbox(x,score=None):
"""
Takes a bounding box in the centre form [x,y,s,r] and returns it in the form
[x1,y1,x2,y2] where x1,y1 is the top left and x2,y2 is the bottom right
"""
w = np.sqrt(x[2]*x[3])
h = x[2]/w
if(score==None):
return np.array([x[0]-w/2.,x[1]-h/2.,x[0]+w/2.,x[1]+h/2.]).reshape((1,4))
else:
return np.array([x[0]-w/2.,x[1]-h/2.,x[0]+w/2.,x[1]+h/2.,score]).reshape((1,5))